二叉树的二叉链表存储结构如何实现

发布网友 发布时间：2022-03-22 15:44

我来回答

共2个回答

懂视网 时间：2022-03-22 20:05

二叉链表存储结构是二叉树的一种存储方式。链表中结点的两个链域分别指向该结点的第一个孩子结点和第二个孩子结点。

　　二叉链表是树的二叉链表实现方式。二叉树是逻辑结构，二叉链表是二叉树的物理实现，两者之间的关系属于概念和实现，抽象和具体的关系。二叉树的顺序存储结构由一组连续的存储单元依次从上到下，从左到右存储完全二叉树的结点元素。对于一般二叉树，应将其与完全二叉树对应，然后给每个结点从1到i编上号，依次存储在大小为i到1的数组中。

　　

热心网友 时间：2022-03-22 17:13

大概这个样子，这个是我以前写的二叉搜索树：
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct node
{
int data,rep;
struct node *left,*right;
} node;
node* insert(node *tree,int x);
int search(node *tree,int x);
node* del(node *tree,int x);
int main()
{
char str[20],ch;
int x;
struct node *tree = NULL;
gets(str);
while (strcmp(str,"quit"))
{
if (!strcmp(str,"insert"))
{
scanf("%d",&x);
tree = insert(tree,x);
}
else if (!strcmp(str,"delete"))
{
scanf("%d",&x);
tree = del(tree,x);
}
else if (!strcmp(str,"search"))
{
scanf("%d",&x);
if (search(tree,x))
puts("Found!");
else
puts("Not Found!");
}
else
puts("There is an error!");
ch = getchar();
gets(str);
}
return 0;
}
node* insert(node *tree,int x)
{
if (tree == NULL)
{
tree = (struct node *)malloc(sizeof(struct node *));
tree->data = x;
tree->rep = 1;
tree->left = (struct node *)malloc(sizeof(struct node *));
tree->right = (struct node *)malloc(sizeof(struct node *));
tree->left = NULL;
tree->right = NULL;
}
else if (tree->data == x)
tree->rep++;
else if (x < tree->data)
tree->left = insert(tree->left,x);
else if (x > tree->data)
tree->right = insert(tree->right,x);
return tree;
}
int search(node *tree,int x)
{
if (tree == NULL)
return 0;
else if (tree->data == x)
return 1;
else if (x < tree->data)
return search(tree->left,x);
else if (x > tree->data)
return search(tree->right,x);
}
node* del(node *tree,int x)
{
struct node *p,*q;

if (tree == NULL) {}
else if (x < tree->data)
tree->left = del(tree->left,x);
else if (x > tree->data)
tree->right = del(tree->right,x);
else if (tree->data == x)
{
if (tree->rep > 1)
tree->rep--;
else
{
if (tree->left == NULL)
return tree->right;
else if (tree->right == NULL)
return tree->left;
else
{
p = tree->left;
q = tree;
while (p->right)
{
q = p;
p = p->right;
}
tree->data = p->data;
tree->rep = p->rep;
q->right = p->left;
}
}
}
return tree;
}来自：求助得到的回答