怎样用MATLAB求 x./(x+386).*0.9994.^(x+386) 在x=662处的3阶泰勒展开

发布网友 发布时间：2022-03-25 19:53

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热心网友 时间：2022-03-25 21:23

假设是五阶展开。
syms
x
taylor(x/(x+386)*0.9994^(x+386),x,'ExpansionPoint',662,'order',5)
最后结果是：
ans
=
(331*exp(1048*log(4997/5000)))/524
+
(x
-
662)^2*((331*exp(1048*log(4997/5000))*log(4997/5000)^2)/1048
-
(193*exp(1048*log(4997/5000)))/575511296
+
(193*exp(1048*log(4997/5000))*log(4997/5000))/549152)
+
(x
-
662)*((193*exp(1048*log(4997/5000)))/549152
+
(331*exp(1048*log(4997/5000))*log(4997/5000))/524)
+
(x
-
662)^4*((193*exp(1048*log(4997/5000))*log(4997/5000)^3)/3294912
-
(193*exp(1048*log(4997/5000))*log(4997/5000)^2)/1151022592
-
(193*exp(1048*log(4997/5000)))/632086358441984
+
(331*exp(1048*log(4997/5000))*log(4997/5000)^4)/12576
+
(193*exp(1048*log(4997/5000))*log(4997/5000))/603135838208)
+
(x
-
662)^3*((193*exp(1048*log(4997/5000)))/603135838208
+
(193*exp(1048*log(4997/5000))*log(4997/5000)^2)/1098304
+
(331*exp(1048*log(4997/5000))*log(4997/5000)^3)/3144
-
(193*exp(1048*log(4997/5000))*log(4997/5000))/575511296)
希望帮到你